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    				| 1. | 3. Calculate the work done when 1.0 mol of water at373 K vaporizes against an atmospheric pressure of1.0 atmosphere. Assume ideal gas behaviour | 
| Answer» We know, PV=nRT V=nRT/P V= 1×0.0821×373/1=30.6L=30.6×10-3m3 Volume of liquid water can be taken negligible and thusΔV=30.6L W=-PΔV=-101325×30.6×10-3m3=-3100J Negative sign indicates that work is done by the system. | |