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3 equal cubes are placed adjacently in a row . find the ratio of the total surface area of the resulting cuboid to that of the sum of the surface area of 3 cubes . |
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Answer» SURFACE area of cube = 6a² cm² sum of the 3 cubes = 6a² ⁼ 18a² cm² length of resulting cuboid = 3a cm breadth of resulting cuboid = a cm height of resulting cuboid = a cm total surface area = 2 ( lb + bh + hl )
ratio = t.s.a of resulting cuboid / area of cube ratio = 18a²/ 14a² ratio = 7/9 ratio = 7:9
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