1.

3 equal cubes are placed adjacently in a row . find the ratio of the total surface area of the resulting cuboid to that of the sum of the surface area of 3 cubes .​

Answer»

Let each SIDE of CUBE = a cm

SURFACE area of cube = 6a² cm²

sum of the 3 cubes = 6a² ⁼ 18a² cm²

length of resulting cuboid = 3a cm

breadth of resulting cuboid = a cm

height of resulting cuboid = a cm

total surface area = 2 ( lb + bh + hl )

  • 2 ( 3a*a + a*a + a *3a )
  • 2 ( 3a² + a + 3a² )
  • 2 ( 7a² )
  • 14a² cm²

ratio = t.s.a of resulting cuboid / area of cube

ratio = 18a²/ 14a²

ratio = 7/9

ratio = 7:9



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