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3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042N. The amont of acetic acid absorbed (pr gram of charcoal) is |
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Answer» Solution :Milleq of acetic acid present initially `=0.06xx60=3` millieq of acetic acid left after adsorption `=0.042xx50=2.1` `THEREFORE` millieq of acetic acid adsorbed by 3 g of charcoal `=3-2.1=0.9meq=0.9xx60 mg=54mg` `therefore` Amount of acetic acid adsorbed per GRAM of charcoal `=54/3=18` mg |
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