1.

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042N. The amount of acetic acid absorbed (per gram of charcoal) is

Answer»

18 mg
36 mg
42 mg
54 mg

Solution :INITIAL m moles of `CH_(3)COOH=0.06xx50`
FINAL m moles of `CH_(3)COOH=0.043xx50`
Hence, MASS of `CH_(3)COOH` adsorbed per gram of
charcoal`=((0.06-0.042)xx50xx10^(-3)xx60xx10^(3))/(3)=18mg`


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