1.

3 identical capacitors are joined in parallel and are charged with a battery of 10 V. Now the batteryis removed and they are joined in series with each other in this condition what would be the potential difference between the freed plates in the combination?

Answer»

30 V
10 V
60 V
`(10)/(3) V `

Solution :When these 3 CAPACITORS are joined in SERIES, p.d. between free PLATES is V.
`:. V = (10 + 10 +10) V`
`:. V = 30 V `


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