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3. In the figure mZBAC = 55°Chord AB = chord ACFind i) m(arc BZC) ii) m(arc AxB) iii) mL ABC |
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Answer» Answer: ) It is given that LINE AB is tangent to the circle at A. ∴ ∠CAB = 90º (Tangent at any point of a circle is perpendicular to the radius throught the point of contact) Thus, the measure of ∠CAB is 90º. (2) Distance of point C from AB = 6 cm (Radius of the circle) (3) ∆ABC is a right triangle. CA = 6 cm and AB = 6 cm Using Pythagoras THEOREM, we have BC2=AB2+CA2⇒BC=62+62−−−−−−√ ⇒BC=62–√ cm Thus, d(B, C) = 62–√ cm |
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