3 moles of ideal gas `X (C_(p,m) = (5)/(2))` and 2 moles of ideal gas `Y(C_(p,m) = (7)/(2)R)` are taken in vessa and compressed reversibly and adiabitically, during this process temperature of gaseous mixture increased from 300 K to 400 K. Calculate change in internal energy `(DeltaU)` in cal of gaseous mixture (Given `R = 2 cal//mol.K`)

3 moles of ideal gas `X (C_(p,m) = (5)/(2))` and 2 moles of ideal gas

1.	3 moles of ideal gas `X (C_(p,m) = (5)/(2))` and 2 moles of ideal gas `Y(C_(p,m) = (7)/(2)R)` are taken in vessa and compressed reversibly and adiabitically, during this process temperature of gaseous mixture increased from 300 K to 400 K. Calculate change in internal energy `(DeltaU)` in cal of gaseous mixture (Given `R = 2 cal//mol.K`)
Answer» Correct Answer - 1900 cal `DeltaU = DeltaU_(1) + DeltaU_(2)` `n_(1)C_(V_(1)m)DeltaT + n_(2)C_(V_(1)m)DeltaT` `=[3 xx(3)/(2)R xx 100 ]+[2 xx (5R)/(2)xx100]` `= 450 R + 500 R` `= 950 R` `= 1900 cal`

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