1.

3 moles of ideal gas X (C_(p,m) = (5)/(2)) and 2 molesof idealgas Y(C_(p,m) = (7)/(2)R) are takenin vessa andcompressed reversibly and adiabitically, duringthisprocess temperatureof gaseousmixture increasedfrom300 K to 400 K. Calculate change in internal energy (DeltaU) in cal of gaseous mixture (Given R = 2 cal//mol.K)

Answer»


Solution :`DELTAU =DeltaU_(1) + DeltaU_(2)`
`n_(1)C_(V_(1)m)DELTAT + n_(2)C_(V_(1)m)DeltaT`
`=[3 XX(3)/(2)R xx 100 ]+[2 xx (5R)/(2)xx100]`
`= 450 R + 500 R`
`= 950 R`
`= 1900 cal`


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