3)P=4Q7. The resultant of two equal forces is 141.4N when they are mut

1.	3)P=4Q7. The resultant of two equal forces is 141.4N when they are mutually pertually perpendicular,they are inclined at an angle 120Â°, then the resultant force will be1100 N4) Zero2) 141.4 N3) 196 N
Answer» When angle is 90° F_net = F√2141.4 = F√2F = 141.4/√2F = 100 N Each force is 100 N When angle is 120° F_net = F Resultant force will be 100N

3)P=4Q7. The resultant of two equal forces is 141.4N when they are mutually pertually perpendicular,they are inclined at an angle 120Â°, then the resultant force will be1100 N4) Zero2) 141.4 N3) 196 N

Answer»

When angle is 90° F_net = F√2141.4 = F√2F = 141.4/√2F = 100 N

Each force is 100 N

When angle is 120° F_net = F

Resultant force will be 100N