1.

3-Phenylpropene on reaction with HBr gives (as a major product)

Answer»

`C_6H_5CH_2CH(Br)CH_3`
`C_6H_5CH(Br)CH_2CH_3`
`C_6H_5CH_2CH_2CH_2Br`
`C_6H_5CH(Br)CH=CH_2`

Solution :According to Markownikoff's rule , the negative part of the UNSYMMETRICAL REAGENT adds to LESS hydrogenated (more substituted ) carbon ATOM of the double bond.
`C_6H_5CH=CH-CH_3+HBr to oversetoverset(Br)(|)(C_6H_5CHCH_2CH_3)`


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