1.

3-Phenylpropene on reaction with HBr gives (as a major produt)

Answer»

`C_(6)H_(5)CH_(2)CH(BR)CH_(3)`
`C_(6)H_(5)CH(BrCH_(2)CH_(3)`
`C_(6)H_(5)CH_(2)CH_(2)CH_(2)Br`
`C_(6)H_(5)CH(Br)CH=CH_(2)`

Solution :According to Markownikoff.s rule, the negative part of the ATTACKING reagent adds to less hydrogenated (more substituted) carbon atom of the double bond.
`C_(6)H_(5)CH_(2)CH=CH_(2)+HBr to C_(6)H_(5)CH_(2)-underset("Br ")underset("| ")("C ")H=CH_(3)`


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