Saved Bookmarks
| 1. |
3) Solve the following quadratic equation by factorization method |
|
Answer» d Answer:-Given:3x² - 2√6x + 2 = 0To Find:The roots of the given QUADRATIC equation.Solution:We have, ➡ 3x² - 2√6x + 2 = 0We need to split -2√6 into two PARTS whose sum is -2√6 and product is 6.We found, -√6 - √6 = -2√6(-√6) × (-√6) = 6Therefore, ➡ 3x² - √6x - √6x + 2 = 0➡ √3x(√3x - √2) - √2(√3x - √2) = 0➡ (√3x - √2)(√3x - √2) = 0By zero product rule, ➡ Either (√3x - √2) = 0 or (√3x - √2) = 0➡ x = √(2/3), √(2/3)★ HENCE, the roots of the given quadratic equation are √(2/3) and √(2/3) [EQUAL Roots]Answer:Zeros are - √(2/3), √(2/3) |
|