InterviewSolution
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InterviewSolution
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3) The velocity ofacan at 10:50 am is 60 kmperhour and at10:52 an it is 80kmper hour assumingconstant accelerationwas the given period find the value. |
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Answer» Answer: Given ▪️Velocity at 10:50 am = 60 km/h = 60 × 5/18 = 150/9 m/s ▪️Velocity at 10:52 am = 80 km/h = 80 × 5/18 = 200/9 m/s ▪️Acceleration is constant Now from above ▪️Time = 2 min = 120 sec Now as we have ▪️v = U + at \longrightarrow \dfrac{200}{9}= \dfrac{150}{9} + 120(a)⟶ 9 200
= 9 150
+120(a) \longrightarrow \dfrac{200}{9}- \dfrac{150}{9} = 120(a)⟶ 9 200
− 9 150
=120(a) \longrightarrow \dfrac{200 - 150}{9}= 120(a)⟶ 9 200−150
=120(a) \longrightarrow \dfrac{50}{9}= 120(a)⟶ 9 50
=120(a) \longrightarrow a = \dfrac{\dfrac{50}{9}}{120}⟶a= 120 9 50
\longrightarrow a = \dfrac{50}{9\times120}⟶a= 9×120 50
\longrightarrow a = \dfrac{5}{9\times12}⟶a= 9×12 5
\longrightarrow a = \dfrac{5}{108}⟶a= 108 5
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