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3.What mass of calcium chloride in grams wouldbe enough to produce 14.35 gm of AgCl.(At. mass Ca = 40, Ag = 108) - |
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Answer» CaCl₂ + 2Ag → 2AgCl + 2Ca ✓ Equivalent of CaCl₂ = Equivalent of AgCl Eʷ = Mʷ / 2 ⇒ w × 2 / 111 = 14. 35 / 143. 5 ⇒ W = 5. 55 g 40 multiply by 108it is a correct answer |
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