1.

3. What should be added to equation 1 to get equation 2Equation 1 : 04-3a²+2a+5 ; Equation 2 : a-2a-a+7​

Answer»

3a²-4a-2.Step-by-step explanation:LET the no. be xThen, 4-3a²+2a+5 + X = a-2a-a+7  [Transpose 4-3a²+2a+5 to the RHS]=>x=a-2a-a+7-4+3a²-2a-5=>x =3a²-4a-2Thus, 3a²-4a-2 should be ADDED to 4-3a²+2a+5  to get a-2a-a+7.



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