3 X square + x square + 2 X + 5 x cube + 2 X + 1 se

1.	3 X square + x square + 2 X + 5 x cube + 2 X + 1 se
Answer» Step-by-step explanation: Given EXPRESSION is:- $3 {x}^{2} + {x}^{2} + 2x + 5 {x}^{3} + 2x + 1 \\ 4 {x}^{2} + 4x + 5 {x}^{3} + 1$ Just in case the question asked you to factorise the WHOLE thing, $4x(x + 1) + 1(x + 1) \\ (4x + 1)(x + 1)$ Therefore it is factorised. If you wanted TWO SOLUTIONS of x, $4x + 1 = 0 \\ x = \frac{ - 1}{4}$ One solution is -1/4 The other is, $x + 1 = 0 \\ x = - 1$ -1

Answer»

Step-by-step explanation:

Given EXPRESSION is:-

$3 {x}^{2} + {x}^{2} + 2x + 5 {x}^{3} + 2x + 1 \\ 4 {x}^{2} + 4x + 5 {x}^{3} + 1$