1.

30 g. of acetic acid is dissolved in 1 dm^(3) of a solvent. The molality of the solution will be (Givent, density of solvent =1.25 g cm^(-3)

Answer»

`0.40`
`0.35`
`0.55`
`0.25`

SOLUTION :`m=W_(2)/(M_(2) xx W_(1) kg)=30/(60 xx 1 xx 1.25 kg )=0.4`


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