1.

30 g of urea (M=60 g mol^(-1)) is dissolved in 864 g of water. Calculater the vapour pressure of water for this soution if vapourpressure of pure waer at 298 K is 23.8 mm Hg.

Answer»


SOLUTION :ACCORDING to RAOULT's Law
`(P_(A)^(@)-P_(S))/P_(S)=W_(B)/M_(B)xxM_(A)/W_(A)`
`((23.8mm)-P_(S))/P_(S)=((30g)xx(18" G mol"^(-1)))/((60" g mol"^(-1))xx(846 g))=0.0106`
`(23.8 mm)-P_(S)=0.02106xxP_(S)`
`(23.8 mm)=1.0106xxP_(S)`
`P_(S)=((23.8 mm))/(1.0106)=23.55mm`


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