30 " mL of " a solution containing `9.15gL^(-1)` of an oxalate `K_(x)H_(y)(C_2O_4)_2.nH_2O` required for titration 27 " mL of " 0.12 N NaOH and 36 " mL of " 0.12 N `KMnO_4` for oxidation Find x,y,z. and n.

30 " mL of " a solution containing `9.15gL^(-1)` of an oxalate `K_(x)H

1.	30 " mL of " a solution containing `9.15gL^(-1)` of an oxalate `K_(x)H_(y)(C_2O_4)_2.nH_2O` required for titration 27 " mL of " 0.12 N NaOH and 36 " mL of " 0.12 N `KMnO_4` for oxidation Find x,y,z. and n.
Answer» Normality of oxalate as an acid`=(27xx0.12)/(30)=0.108` Ew of oxalate as acid `=("strength")/(N)=(9.15)/(0.108)=84.72` Normality of oxalate as reducing agent`=(36xx0.12)/(30)` `=0.144` Ew of oxalate as reducing agent`=(9.15)/(0.144)=63.54` Oxalate as acid: `(Mw)/(y)=84.72` Oxalate as reducing agent `(Mw)/(2z)=63.54` `x+y=2z` `y=15z` `thereforex:y:z=1:3:2` `therefore39xx1+3xx1+2xx88+18n=254` `n=2` Formula is `KH_3(C_2O_4).2H_2O`

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