1.

300 mL mixture of ethylene and Butylenen is burnt in presence of oxgen then 150mL of oxygen is required, what is the volume of Ethylenen & Butylene in mixute.

Answer»

Solution :Let the volume of `C_(2)H_(4)=x mL`
So volume of Butylene `=(30-x)mL`
For `C_(2)H_(4)C_(2)H_4)+3O_(2)rarr2CO_(2)+2H_(2)O`
from equation
`because` for `1` volume `C_(2)H_(4). 3` volume of `O_(2)` is required.
`because` for `x mL` vol. of `C_(2)H_(4), 3x ml` volume of `O_(2)` is required.
For `C_(4)H_(8)``C_(4)H_(8)+6O_(2)rarr4CO_(2)+4H_(2)O`
`because` for `1` volume `C_(4)H_(8)' 6` volume of `O_(2)` is required.
Total volume of `O_(2)=3x+6(30-x)mL=150 mL` (Given)
`x=10`
`because` Volume of `C_(2)H_(4)` in mixture is `10ML`
`because` Volume of `C_(2)H_(4)` in mixture is `20mL`


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