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√ √32.4. Find the zero of the polynomial in each of the following cases0 p(x)=x+5@ p(x)=x-5m) p(x)=2x+5(iv) p(x)=3x-2(v) p6r) = 3(vi) p(x)= ar, a=0(vii) p(x)=x+d.c#0, c, d are real numbers. |
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Answer» <P>Step-by-step explanation: p(x)=x+5 x+5=0 x= -5p(x)=x-5 x-5=0 x=5p(x)=2x+5 2x+5=0 2x= -5 x= -5/2p(x)=3x-2 3x-2=0 3x=2 x=3/2p(6r)=3 6r=3 r=2 p(x)=ar ar=0 0×r=0 r=0p(x)=x+d |
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