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32. In Fig. 15.106, the area of segment ACB is (a) w (--(5)- • (-3) - (a) None of these 120 A B С Fig. 15.106 |
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Answer» Answer: Answer Given angle of arc = 120 degrees =3.14*21*21 =1386 cm2 Area of Arc= (angle of arc/ 360)*area of circle = (120 /360)*1386 =1386/3 =462 cm2 Area of triangle = a*b*sinx / 2 =21*21*sin(120) /2 =190.96 cm2 Area of segment = area of arc - area of triangle =462 - 190.96 =271.04 cm2 |
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