321n open flask at 25°C contains air. Calculate thetemperature at whi

1.	321n open flask at 25°C contains air. Calculate thetemperature at which one fifth of air measured a25°C escapes.
Answer» According to Charle's law - T is directly proportion to VThus V1/V2 =T1/T21 /1/5=298/T2(Let volume at initial is 1 and after 27℃ temp. Volume remains 1/5 of initial volume)T2=T2=396K but ans is 99.5 degres celsius

321n open flask at 25°C contains air. Calculate thetemperature at which one fifth of air measured a25°C escapes.

Answer»

According to Charle's law - T is directly proportion to VThus V1/V2 =T1/T21 /1/5=298/T2(Let volume at initial is 1 and after 27℃ temp. Volume remains 1/5 of initial volume)T2=T2=396K

but ans is 99.5 degres celsius

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321n open flask at 25°C contains air. Calculate thetemperature at which one fifth of air measured a25°C escapes.

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