1.

34 g of hydrogen peroxide is present in 1120 ml of Solution. This solution is called

Answer»

10 VOLUME
20 volume
30 volume
32 volume

Solution :Wt. of `H_(2)O_(2) " in " 1 ml = 34/(1120) `G
` H_(2)O_(2) to H_(2)O + 1/2 O_(2)`
34 g of `H_(2) O_(2) ": gives " 11200 " MLOF " O_(2) ` at STP .
` :34/(1120) " g of " H_(2)O_(2) -= (11200)/34 xx 34/(1120) = 10 " ml of " O_(2) ` at STP .


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