34. Number of moles of MnO required to oxidizeone mole of ferrous oxal

1.	34. Number of moles of MnO required to oxidizeone mole of ferrous oxalate completely in acidicmedium will be:(a) 0.6 moles(c) 7.5 moles (d) 0.2 moles12008)(b) 0.4 moles
Answer» 10FeC2O4+ 6KMnO4+ 24H2SO4----> 3K2SO4+ 6MnSO4+ 5Fe2(SO4)3+ 24H2O +20CO2 So we see that 6 moles of KMnO4is required to oxidize 10 moles of FeC2O4 Then, 1 mole of FeC2O4would be oxidized by = ? 6/10=0.6

34. Number of moles of MnO required to oxidizeone mole of ferrous oxalate completely in acidicmedium will be:(a) 0.6 moles(c) 7.5 moles (d) 0.2 moles12008)(b) 0.4 moles

Answer»

10FeC2O4+ 6KMnO4+ 24H2SO4----> 3K2SO4+ 6MnSO4+ 5Fe2(SO4)3+ 24H2O +20CO2

So we see that

6 moles of KMnO4is required to oxidize 10 moles of FeC2O4

Then, 1 mole of FeC2O4would be oxidized by = ?

6/10=0.6