35. In hydrogen atom, energy of first excited stateis-3.4 eV. Then fin – InterviewSolution

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1.	35. In hydrogen atom, energy of first excited stateis-3.4 eV. Then find out K.E. of same orbitof hydrogen atom(a) +3.4 ev(c) 13.6 eV(b) +6.8 eV(d) +13.6 eV (2002)
Answer» option a is the answer.KE is the energy with which the electron moves in the orbit hence The energy is same but positive so answer is 3.4eV

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