1.

36g water and 828g ethyl alcohol form an ideal solution. The mole fraction of water in it, is

Answer»

`1.0`
`0.7`
`0.4`
`0.1`

Solution :`N=(W)/(M)=(828)/(46) = 18, n =(w)/(m)=(36)/(18)=2`
`x_(H_(2)O)=(n)/(n+N)=(2)/(2+18)=(2)/(20)=0.1`


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