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37, Hf the gravitational force between two objectswereproportional to 1/R (and not as 1/R2), where R isthe distance between them, then a particle in acircular path (under such a force) would have itsorbital speed v, proportional to |
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Answer» Given here: F∝1/Ror,F =kRNow, when one of the particles goes around the other then it is acted upon by a centripetal force given by: Fcentri= mv2/Rnow, mv2/R = kR v =R√(k/m)orv∝ R |
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