1.

3A t0 2B ,rate of reaction + (d[B])/(dt)is equal to

Answer»

`-(3)/(2) (d[A])/(dt)`
`-(2)/(3)(d[B])/(dt)`
`+2(d[A])/(dt)`
`-(1)/(3)(d[A])/(dt)`

Solution : `:-(1)/(3)(d[A])/(dt)=+(d[B])/(dt)`
`-(2)/(3)(d[A])/(dt)=+(d[B])/(dt)`


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