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3t-2/4-2t+3/3=2/3-tpls solve this linear algebra |
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Answer» d answerStep-by-step EXPLANATION:Given(3t−2)/4−(2t+3)/3=2/3−tNow by taking L.C.M for 4 and 3 is 12(3(3t−2)−4(2t+3))/12=2/3−tBy TRANSPOSING the above equation we can WRITE as (9t−6−8t−12)/12=2/3−tt+12t=8+18Again by transposingt = 26/13t = 2 |
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