1.

3u-5v+1=0, 2u-v+3=0 cross multiplication​

Answer»

Answer:

2(3u−v)=5uv ....(1)

2(u+3v)=5uv ....(2)

From (1) and (2) we get

2(3u−v)=2(u+3v)

⇒3u−v=u+3v

⇒3u−u=3v+v

⇒2u=4v

⇒u=2v

Substitute u=2v in (1) we get

2(3×2v−v)=5×2v×v

⇒6v−v=5×v

2

⇒5v=5×v

2

⇒v=v

2

⇒v

2

−v=0

⇒v(v−1)=0

⇒v=0,v=1

Put v=0 in u=2v⇒u=0

∴u=0,v=0u=2,v=1


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