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(3x+1)^2+6x=0, find x or y if possible. Thank you to anyone willing to help!

Answer»

9x^2+6x+1+6x=09x^2+12x+1=0by FORMULA, X= -b±√(b²-4ac))/(2A)x= (-12±√(12^2-4*9*1))/2*9x= (-12±√108)/18x= (-12/18)±(√108/18)x= (-2/3)±(6√3/18)x= (-2/3)±(1/√3)therefore,x=(-2/3)+(1/√3) or x=(-2/3)-(1/√3)



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