1.

3x-2y =5 and 3y-2y=3 by elimination method ​

Answer»

Answer :

x = 21/5 , y = 19/2

Solution :

Here ,

The given equations are ;

3x - 2y = 5 ----------(1)

3y - 2x = 3 ------------(2)

EQ-(2) can be rewritten as ;

-2x + 3y = 3 ---------(3)

Now ,

Multiplying eq-(1) by 3 , we get ;

=> 3•(3x - 2y) = 3•5

=> 9x - 6y = 15 ------------(4)

Also ,

Multiplying eq-(3) by 2 , we get ;

=> 2•(-2x + 3y) = 2•3

=> -4x + 6y = 6 ----------(5)

Now ,

ADDING eq-(4) and (5) , we get ;

=> 9x - 6y - 4x + 6y = 15 + 6

=> 5x = 21

=> x = 21/5

Now ,

Putting x = 21/5 in eq-(1) , we get ;

=> 3x - 2y = 5

=> 3•(21/5) - 2y = 5

=> 63/5 - 2y = 5

=> 2y = 63/5 - 5

=> 2y = (63 - 25)/5

=> 2y = 38/5

=> y = 38/(5•2)

=> y = 19/2

Hence ,

x = 21/5 , y = 19/2



Discussion

No Comment Found

Related InterviewSolutions