4.35 g of a mixture of NaCl and Na_(2)CO_(3) was dissolved in 100 mL of water , 20 mL of which was exactly neutralised by 75.5mL of N/0 solution of H_(2)SO_(4) . Calculate the percentageof NaCl and na_(2)CO_(3) in the mixture .

4.35 g of a mixture of NaCl and Na_(2)CO_(3) was dissolved in 100 mL o

1.	4.35 g of a mixture of NaCl and Na_(2)CO_(3) was dissolved in 100 mL of water , 20 mL of which was exactly neutralised by 75.5mL of N/0 solution of H_(2)SO_(4) . Calculate the percentageof NaCl and na_(2)CO_(3) in the mixture .
Answer» Solution :In this problem ,`Na_(2)CO_(3)`is neutralised by `H_(2)SO_(4)` solution . Let the amount of `Na_(2)CO_(3)` be x g . ` :. ` equivalent of `na_(2)CO_(3)` in 100 ML in solution = `x/53 ` …(Eqn.4i) ` :. ` m.e of `Na_(2)CO_(3)` in10 mLof solution` = x/53 xx1000 "" ...(Eqn.3)` ` :. ` m.e of `na_(2)CO_(3)` in 20 mL of solution ` = (1000 x)/53 xx20/100 = (200 x)/53 ` Now , m.e of `H_(2)SO_(4)` solution ` = 1/10 xx 75.50 "" ...(Eqn.1)` `:. ` m.e of `Na_(2)CO_(3) ` = m.e of `H_(2)SO_(4) "" ...(Eqn.2)` ` :. "" (200x)/53 = 7.55 ` x = 2 ` :. "" % of Na_(2)CO_(3) = 2/(4.35) xx 100= 45.99 % ` ` % of naCl = 100 - 45.99 = 54.01 % `