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4.4m2.r diameter of a circults inner curved surface area,If the radius of the base of thear well is 3.5 m. It is 10 m deep Finde innerits inner curvecthe cost of plasterinf plastering this curved surface at the rate of 40 per ma a hotwater heating system, there is a cylindrical niheatin

Answer» <p>Curved surface area = 2 x pi x r x h= 2 x 3.14 x 1.75 x 10 = 110.25 m^2Cost = rate x area= 40 x 110.25 = 4410.</p>


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