1.

4.5 gm of aluminium (atomic mass 27 amu) get deposited on cathode by passing fixed amount of electricity through Al^(3+) solution. So what is the volume of hydrogen gas at STP by passing same amount of electricity through H^(+) solution.

Answer»

44.8 L
22.4 L
11.2 L
5.6 L

Solution :NUMBER of grams in equivalence of `H^(+)`=Number of grams in equivalence of `Al^(3+)`
EQUIVALENT weight of `Al^(3+)=(27)/(3)=9`
`Al^(3+)=(4.5)/(9)=0.5`
Number of grams in equivalence of `H^(+)`=number of moles of `H^(+)`
So, equivalent weight of `H^(+)=0.5xx1.0gm`
`=0.5gm` of `H_(2)`
As we know that, 2 gm `H_(2)` at STP=22.4 L
So, at STP, 0.5 gm `H_(2)=(22.4)/(2)xx0.5=5.6L`


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