1.

4.6 gm of liquid ethanol (C_(2)H_(5)OH) is taken in 12 litre container and at 27^(@)C, 40% of ethanol is vaporised till equilibrium. Now if volume of container is halved and system is allowed to attain equilibrium then find [Give: R=0.08atm/litre mole-k]

Answer»

Solution :`C_(2)H_(5)OH(L)hArrC_(2)H_(5)OH(g)`
Molet=0 0.1 0
`t=t_("eqm") 0.1-0.04 0.04`
=0.06
For gas PV=nRT `rArrP_(C_(2)H_(5)OH("gas"))=(nRT)/(V)=(0.04xx0.08xx300)/(12)`
`V.P_("gas")=0.08` atm (at `eq^(m)`)
=0.08xx100=8


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