1.

4+8+12......+160What is the sum?????

Answer»

Answer:

Step-by-step EXPLANATION:

A is 1st term

L is LAST term

n is number of terms

d is common difference

     nth term= A + (n- 1 )d

     160 = 4 + ( n-1) 4

     156 = (n - 1) 4

     39 = n-1

      n=40

sum = n/2 ( A+ L)

       =  40 / 2 ( 160 + 4)

       = 20 ( 164)

       = 3280

hope it helps

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