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4+8+12......+160What is the sum????? |
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Answer» Answer: Step-by-step EXPLANATION: A is 1st term L is LAST term n is number of terms d is common difference nth term= A + (n- 1 )d 160 = 4 + ( n-1) 4 156 = (n - 1) 4 39 = n-1 n=40 sum = n/2 ( A+ L) = 40 / 2 ( 160 + 4) = 20 ( 164) = 3280 hope it helps plss mark as BRAINLIEST |
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