1.

4.9 g of H_(2) SO_(4) is present in500 cm^(3) of the solution has molarity.

Answer»

0.2
0.1
0.01
0.02

Solution :`M= "Mass"/("Molar mass" xx V (DM^(3)))`=`4.9/(98 xx 5)=1/10=0.1`


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