1.

4.90 g of KClO_(3) when heated produced 1.92 g of oxygen and the residue (KCl) left behind weighs 2.96 g. Show that these results illustrate the law of conservation of mass.

Answer»

Solution :Mass of `KClO_(3)` taken = 4.90 g
TOTAL mass of the product `(KCl+O_(2))=2.96+1.92=4.88g`
Difference betweenthe mass of the reactant and the total mass of the PRODUCTS = `4.90-4.88=0.02g`
This small difference may be DUE to EXPERIMENTAL error.
THUS, law of conservation of mass holds good within experimental errors.


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