4) Find the length of the median BE of A ABC where A = A = (10, 6),B

1.	4) Find the length of the median BE of A ABC where A = A = (10, 6),B = (-2, 2) and C = (6, 10).
Answer» ONG>Step-by-step EXPLANATION: MIDPOINT of AC $( \frac{x1 + x2}{2} \frac{y1 + y2}{2}) = \\ ( \frac{10 + 6}{2} \frac{10 + 6}{2}) = (8 \: 8) \\ length \:of \: median = \\ \$ $\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } \\ = \sqrt{ {( - 2 - 8)}^{2} + {(2 - 8)}^{2} } \\ = \sqrt{100 + 36} \\ = \sqrt{136} units$

4) Find the length of the median BE of A ABC where A = A = (10, 6),B = (-2, 2) and C = (6, 10).

Answer» ONG>Step-by-step EXPLANATION:

$( \frac{x1 + x2}{2} \frac{y1 + y2}{2}) = \\ ( \frac{10 + 6}{2} \frac{10 + 6}{2}) = (8 \: 8) \\ length \:of \: median = \\ \$

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } \\ = \sqrt{ {( - 2 - 8)}^{2} + {(2 - 8)}^{2} } \\ = \sqrt{100 + 36} \\ = \sqrt{136} units$