Step-by-step explanation:1)  12283First find the PRIME factors for 1228312283 = 3×3×3×23×23By GROUPING the prime factors in equal pairs we GET,= (3×3) × (23×23) × 3By observation, prime factor 3 is left out.So, divide by 3 to eliminate 3 we get,12283/3 = (3×3) × (23×23)= (3×23) × (3×23)= 69 × 69= (69)2So the SQUARE of 12283 is 4761.====================================2) 1800First find the prime factors for 18001800 = 2×2×5×5×3×3×2By grouping the prime factors in equal pairs we get,= (2×2) × (5×5) × (3×3) × 2By observation, prime factor 2 is left out.So, divide by 2 to eliminate 2 we get,1800/2 = (2×2) × (5×5) × (3×3)= (2×5×3) × (2×5×3)= 30 × 30= (30)2So the square of 1800 is 900.====================================3) 2904First find the prime factors for 29042904 = 2×2×11×11×2×3By grouping the prime factors in equal pairs we get,= (2×2) × (11×11) × 2 × 3By observation, prime factor 2 and 3 are left out.So, divide by 6 to eliminate 2 and 3 we get,2904/6 = (2×2) × (11×11)= (2×11) × (2×11)= 22 × 22= (22)2So the square of 2904 is  484.====================================