1.

4. Find two numbers such that one of them is 8 more than theother and their sum equals to 64

Answer»

ANSWER:

Let the FIRST no be x

so second NUMBER will be (x+8)

Step-by-step explanation:

so x+x+8=64

= 2x+8=64

= 2x= 64-8

= 2x= 56

x= 56/2

x= 28

First number= 28

Second number = x+8

= 28+8=36



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