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4. Find two numbers such that one of them is 8 more than theother and their sum equals to 64

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><h2><strong><em>Let </em></strong><strong><em>the </em></strong><strong><em><a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> </em></strong><strong><em>no </em></strong><strong><em>be </em></strong><strong><em>x </em></strong></h2><h2><strong><em>so </em></strong><strong><em>second </em></strong><strong><em><a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> </em></strong><strong><em>will </em></strong><strong><em>be </em></strong><strong><em>(</em></strong><strong><em>x</em></strong><strong><em>+</em></strong><strong><em>8</em></strong><strong><em>)</em></strong></h2><p><strong>Step-by-step explanation:</strong></p><h3><strong><em>so </em></strong><strong><em>x+</em></strong><strong><em>x</em></strong><strong><em>+</em></strong><strong><em>8</em></strong><strong><em>=</em></strong><strong><em>6</em></strong><strong><em>4</em></strong></h3><h3><strong><em>=</em></strong><strong><em> </em></strong><strong><em>2x+</em></strong><strong><em>8</em></strong><strong><em>=</em></strong><strong><em>6</em></strong><strong><em>4</em></strong></h3><h3><strong><em>=</em></strong><strong><em> </em></strong><strong><em>2x=</em></strong><strong><em> </em></strong><strong><em>6</em></strong><strong><em>4</em></strong><strong><em>-</em></strong><strong><em>8</em></strong></h3><h3><strong><em>=</em></strong><strong><em> </em></strong><strong><em>2x=</em></strong><strong><em> </em></strong><strong><em>5</em></strong><strong><em>6</em></strong></h3><h3><strong><em>x=</em></strong><strong><em> </em></strong><strong><em>5</em></strong><strong><em>6</em></strong><strong><em>/</em></strong><strong><em>2</em></strong></h3><h3><strong><em>x=</em></strong><strong><em> </em></strong><strong><em>2</em></strong><strong><em>8</em></strong></h3><h2><strong><em>First </em></strong><strong><em>number=</em></strong><strong><em> </em></strong><strong><em>2</em></strong><strong><em>8</em></strong></h2><h2><strong><em>Second </em></strong><strong><em>number </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em>x+</em></strong><strong><em>8</em></strong></h2><h2><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em>2</em></strong><strong><em>8</em></strong><strong><em>+</em></strong><strong><em>8</em></strong><strong><em>=</em></strong><strong><em>3</em></strong><strong><em>6</em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em> </em></strong></h2></body></html>


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