1.

4 g carbon were heated with 8 g of sulphur. How much carbon disulphide (CS_(2)) will be formed when that reaction is complete ? What will be its percentage purity?

Answer»

Solution :`underset(12g)(C)+underset(2xx32=64g)(2S)rarrunderset(12+2xx32=76g)(CS_(2))`
Obviously, sulphur will be the limiting reactant.
`"8 g sulphur will produce CS"_(2)=(76)/(64)xx8=9.5g`
`"CARBON reacted "=(12)/(64)xx8=1.5g`
`"Carbon left "=4-1.5=2.5g`
`"Total mass of products"=9.5+2.5=12g`
`therefore %" purity of "CS_(2)" in the product "=(9.5)/(12)xx100=79.2%.`


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