1.

4 g of caustic soda (molar mas = 40 g mol^(-1)) are dissolved in water and the solution is made to 200 mL. Calculate the molarity of the solution.

Answer»


Solution :`"Molarity of solution (M)"=("Mass of SOLUTE/Molar mass of solute")/("VOLUME of solution in litres")`
`=(4g//(40" G mol"^(-1)))/((200//1000)L)=0.5" mol L"^(-1)(0.5 M)`


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