1.

4 g of copper was dissolved in concentrated nitric acid. The copper nitrate solutio on strong heating gave 5g of its oxide. The equivalent weight of copper is

Answer»

23
32
12
20

Solution :In 5 gm `CuO,4gm` Cu and 1 gm O be PRESENT.

EMPIRICAL formula `=CuO` of oxide
In this oxide, oxidation no. of Cu=+2
EQUIVALENT weight=`("Molecular weight")/("Oxidation no.")=(63.5)/(2)~~31.75`
But equivalent weight should be an INTEGRAL no.=32.
=9.65A


Discussion

No Comment Found

Related InterviewSolutions