1.

4 gm of the chloroplatinate salt of triacidic base 'B' on ignition gave 1 gm of Platinum then moar mass of base 'B' in gm is -

Answer»

585
555
1110
1170

Solution :`M = (N)/(2) [(w xx 195)/(x) - 410] g mol^(-1)`
`M = (3)/(2) [(4 xx 195)/(1) - 410]`
`M = (3)/(2) [780 - 410] rArr M = 555 gm//mol`


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