1.

4 identical balls of radius R and mass m are lying a gravity free space. The balls are in contact and there centres are forming vertices of a square of side 2R in horizontal plane. One identical ball travelling vertically with a speed v hits the four balls symmetrically. The collision is perfectly elastic. The centre of the 4 stationery ball are at (R, R, 0), (R, -R, 0) and (-R, -R,0) initially. The speed of ball 1 after collision is :

Answer»

`(sqrt(2))/(3)v`
`(v)/(sqrt(2))`
`(6)/(11)sqrt((2)/(3))`
none of these

Solution :`MV=(4mv_(1))/(sqrt(2))+mv_(2)`……(`1`)
`1=(v_(1)=(v_(2))/(sqrt(2)))/(v//sqrt(2))`.....(`2`)
`v_(1)=(sqrt(2)v)/(3)`


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