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4 identical balls of radius R and mass m are lying a gravity free space. The balls are in contact and there centres are forming vertices of a square of side 2R in horizontal plane. One identical ball travelling vertically with a speed v hits the four balls symmetrically. The collision is perfectly elastic. The centre of the 4 stationery ball are at (R, R, 0), (R, -R, 0) and (-R, -R,0) initially. The speed of ball 1 after collision is : |
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Answer» `(sqrt(2))/(3)v` `1=(v_(1)=(v_(2))/(sqrt(2)))/(v//sqrt(2))`.....(`2`) `v_(1)=(sqrt(2)v)/(3)` |
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