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4. If in a ΔABC , angle C=60^° , then show that [1÷(a+c)]+[1÷(b+c)]=[3÷(a+b+c)]

Answer» 4. If in a ΔABC , angle C=60^° , then show that [1÷(a+c)]+[1÷(b+c)]=[3÷(a+b+c)]


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