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4) If sec-m+n÷2√mn find sin |
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Answer» May this ANSWER helped youStep-by-step explanation:Solution:1/m[(m + N) + 1/(m + n)]= 1/m [{(m + n)2 + 1}/ (m + n)]= 1/m [(M2 + n2 + 2MN + 1)/ (m + n)]Substituting sec θ = m and tan θ = n,= 1/sec θ[(sec2θ + tan2θ + 2 sec θ tan θ + 1)/ (sec θ + tan θ)]= 1/sec θ[(sec2θ + sec2θ + 2 sec θ tan θ)/ (sec θ + tan θ)]= 1/sec θ[(2 sec2θ + 2 sec θ tan θ)/ (sec θ + tan θ)]= 1/sec θ[2 sec θ(sec θ + tan θ)/ (sec θ + tan θ)]= 2 sec θ/sec θ= 2 |
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